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Description: 本教程定位于FPGA/CPLD的快速入门。以ALTERA公司的芯片和相应的开发软件为目标载体进行阐述，本教程阐述了ALTERA主要系列芯片PLD芯片的结构和特点以及相应的开发软件MAX和Plusa和Quartus的使用-position in the handbook FPGA / CPLD Quick Start. With Altera's chips and the corresponding development of software for the target vector elaborate, the tutorials explain the main chips Altera PLD chips on the structure and characteristics of the corresponding software development MA Plusa and X and the use Quartus
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Description: 幂法求矩阵的特征值和特征向量
算法9.1
1． 输入矩阵A，初始向量X，误差限ε最大迭代次数N。
2． 置k=1，u=0。
3． 求xr=>λ，|xr|=max|xr|,i=1,….,n。
4． 计算
Y=X/λ，X=AY
5． 若|λ-u|〈ε，输出λ，X，停机；否则，转步骤6。
6. 若k<N，k+1=>k，λ=>u,转步骤3；否则，输出错误信息，停机
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Description: DirectX开发人员使用,3DMax导出X文件插件,解压后考入插件目录-development of the use of DirectX, MAX plug-derived X documents, unpacked admitted plugin directory
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Description: ％ [BestPop,Trace]=fmaxga(FUN,LB,UB,eranum,popsize,pcross,pmutation)
％ Finds a maximum of a function of several variables.
％ fmaxga solves problems of the form:
％ max F(X) subject to: LB <= X <= UB
％ BestPop--------最优的群体即为最优的染色体群
％ Trace----------最佳染色体所对应的目标函数值
％ FUN------------目标函数
％ LB-------------自变量下限
％ UB-------------自变量上限
％ eranum---------种群的代数,取100--1000(默认1000)
％ popsize--------每一代种群的规模；此可取50--100(默认50)
％ pcross---------交叉的概率,此概率一般取0.5--0.85之间较好(默认0.8)
％ pmutation------变异的概率,该概率一般取0.05-0.2左右较好(默认0.1)
％ options--------1×2矩阵,options(1)=0二进制编码(默认0),option(1)~=0十进制编码,option(2)设定求解精度(默认1e-4)
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Description: 1.功能
利用广义逆求解无约束条件下的优化问题(C语言)
2.参数说明
int m : 非线性方程组中方程个数
int n : 非线性方程组中未知数个数
double eps1 : 控制最小二乘解的精度要求
double eps2 : 用于奇异值分解中的控制精度要求
double x[n] : 存放非线性方程组解的初始近似值X(0),要求各分量不全为0
int ka : Ka＝max{m,n}+1
void (*f)() : 指向计算非线性方程组中各方程左端函数值的函数名(用户自编)
void (*s)() : 指向计算雅可比矩阵的函数名
int ngin() : 函数返回一个标志值
3.文件说明
ngin.c函数文件
ngin0.c主函数文件-1. Using generalized inverse function for non-binding under the conditions of optimization problems (C) 2. Parameter Description int m : nonlinear equation group number int n equation : nonlinear equations were unknown number of double eps1 : Least Squares Solutions of control precision double eps2 : for the singular value decomposition of the control precision double x [n] : Nonlinear storage solutions of equations initial approximation of X (0), the requirements for the component failure 0 int ka : Ka = max (m, n) a void (* f) () : Calculation of nonlinear equations at the Group of the equation extreme value of the function name (user self) void (* s) () : at the Jacobian matrix calculation of the function name ngin int () : function returns a value of three signs. This document explains
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Description: function y_cum = cum2x (x,y, maxlag, nsamp, overlap, flag)
％CUM2X Cross-covariance
％ y_cum = cum2x (x,y,maxlag, samp_seg, overlap, flag)
％ x,y - data vectors/matrices with identical dimensions
％ if x,y are matrices, rather than vectors, columns are
％ assumed to correspond to independent realizations,
％ overlap is set to 0, and samp_seg to the row dimension.
％ maxlag - maximum lag to be computed [default = 0]
％ samp_seg - samples per segment [default = data_length]
％ overlap - percentage overlap of segments [default = 0]
％ overlap is clipped to the allowed range of [0,99].-function y_cum cum2x = (x, y, maxlag. nsamp, overlap, flag)% CUM2X Cross-covariance% y_cum cum2x = ( x, y, maxlag, samp_seg, overlap, flag)% x, y-data vectors / matrices with identical dimen sions% if x and y are matrices. rather than vectors. % columns are assumed to correspond to independ ent realizations,% overlap is set to 0, and samp_seg dimension to the row. % maxlag-max imum lag to be computed [default = 0]% samp_seg - samples per segment [default = data_length] o% verlap-percentage overlap of segments [defau lt = 0]% overlap is clipped to the allowed range o f [0,99].
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Description: 功能说明：
次组件提供的功能有二：
1、解析出数学表达式中的参数
2、计算数学表达式
此组件不但可以解析和计算数学表达式，还提供了一系列的数学基本函数，可应用于表达式中一块处理。提供的数学基本函数有：将值舍入到最接近的整数 rount(x)、向下取整函数 int(x)、向上取整 ceiling(x)、求两个数中最大数的函数 max(a,b)、求两个数中最小数的函数 min(a,b)、幂函数 pow(x,n)、求平方根的函数 sqrt(x)。
下载地址：http://www.qiusuo365.com/qiusuo365/viewthread.php?tid=2422&extra=page％3D1-Functional Description : sub-components provided by the two functions : one, to figure out the mathematical expression of two parameters. calculate mathematical expression of this component will not only analytical and computational mathematical expression, but also provided a series of basic math functions, expression can be applied to a handle. The basic function of mathematics : the value of rounding to the nearest integer rount (x), downward for the entire function int (x), up from the entire ceiling (x), 2 for the largest number of the number of function max (a, b), 2 for the smallest number of the number of function min (a, b), power function pow (x, n), for the square root function sqrt (x). Download Address : http : / / www.qiusuo365.com/qiusuo365/viewthread . php tid = 24
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Description: 研究在普通的PC机下开发高质量的视景仿真系统。在Window X P系统下 ， 以Vi s u a l C ++为开发平台， 利用
O p e n GL和 3 D S MA X， 运用面向对象编程的思想， 采用 Wi n 3 2 Ap p l i c a t i o n的编程方法。首先介绍了 Op e n G L及如何利
用 它生成地面和天空 。采用 Op e n GL函数进行摄像漫游和调入 由 3 DS MAX绘 制的 3 DS模型 ， 较好 地解决了用 Op e n GL
绘 制复杂图形的困难性 。
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Description: 很多出学direct3d的人都在转换x文件时犯难，其实可以用3ds max输出的文件，这是实现方法
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Author: zyc |
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Description: ％radon transform
clear all
％
N=800
n=1:N
fs=200
t=n/fs
x1=exp(j*2*pi*(5*t+0.5*5*t.^2))
x2=exp(j*2*pi*(5*t+0.5*15*t.^2))
x=x1+x2
％N=length(x)
％ ambifunb(x )
％*****************************************RAT
naf=ambifunb(x)
htl(abs(naf))
％ [wh,rho,theta]=htl(abs(naf))
colormap([0,0,0])
％ xlabel( 极半径 )
％ ylabel( 角度 )
％**************************************％找出峰值点的坐标,计算初始频率和调频斜率(正确)
％找出峰值点的坐标
b=max(max(wh))
[u,a]=find(wh>=0.8*b)
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Description: AT91S_IPheader IpHeader; int status; AT91F_LowLevelInit(); AT91F_DBGU_Printk("\n\n\r-I- ======================================\n\r"); AT91F_DBGU_Printk("-I- AT91RM9200 EMAC Test\n\r"); AT91F_DBGU_Printk("-I- --------------------------------------\n\r"); //* System Timer initialization AT91F_ST_SetPeriodInterval(AT91C_BASE_ST, AT91C_ST_PITS); AT91F_ST_EnableIt(AT91C_BASE_ST, AT91C_ST_PITS); AT91F_AIC_ConfigureIt ( AT91C_BASE_AIC, // AIC base address AT91C_ID_SYS, // System peripheral ID AT91C_AIC_PRIOR_HIGHEST, // Max priority AT91C_AIC_SRCTYPE_INT_LEVEL_SENSITIVE, // Level sensitive AT91F_ST_ASM_HANDLER ); //* Enable ST interrupt AT91F_AIC_EnableIt(AT91C_BASE_AIC, AT91C_ID_SYS); //* Initialize AT91RM9200 EMAC status = AT91F_EmacEntry(); if (status) { sprintf(MsgBuffer, "Error EMAC init: 0x%x", status); AT91F_DBGU_Printk(MsgBuffer); while(1); } while(1) if (AT91F_ProcessEmacPacket(&IpHeader) == AT91C_IPPACKET) AT91F_DisplayIpPacket(&IpHeader);
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Description: 实验三：C++编程入门
一、实验内容
1. 类模版。
2. 运算符重载。
3. 友元。
4. 继承。
二、实验题目
1， 设计一个类SavingsAccount，定义一个静态数据成员记录存款的年利率（rate），该类的每个成员都包含一个私有的数据成员balance，表示该成员当前的存款数额。提供一个成员函数CalMonthlyInterest()，用以计算月利息（用balance乘以rate再除以12），并将这个月利息加入balance中。提供一个静态成员函数ModifyRate()，用以改变静态数据成员rate的值。定义两个不同的SavingsAccount对象saver1和saver2，当前存款数额balance分别为2000.00和3000.00。首先将rate设置为3%，计算每个存款人的月息并打印新的结果，然后将rate设置为4%，再次计算每个存款人的月息并打印新的结果。
2， 设计一个学生类student，包括学生学号、姓名、成绩；设计一个友元函数，比较某两个学生成绩的高低；读入一个文本文件（格式如示例studengt.txt，每行的学号、姓名、成绩之间用四个空格隔开）中所有学生的学号、姓名、成绩，输出最高成绩和最低成绩的学生信息（学号、姓名、成绩）。
3， 阅读下面例子，将题中的Time类声明为Data类的友元类，通过Time类中的display函数引用Data类的私有数据，输出年、月、日和时、分、秒。
#include <iostream>
using namespace std;
class Date; //对Date类的提前引用声明
class Time //定义Time类
{
public:
Time(int,int,int);
void display(Date &); //display是成员函数，形参是Date类对象的引用
private:
int hour;
int minute;
int sec;
};
class Date //声明Date类
{
public:
Date(int,int,int);
friend void Time∷display(Date &); //声明Time中的display函数为友元成员函数
private:
int month;
int day;
int year;
};
Time∷Time(int h,int m,int s) //类Time的构造函数
{
hour=h;
minute=m;
sec=s;
}
void Time∷display(Date &d) //display的作用是输出年、月、日和时、分、秒
{
cout<<d.month<<″/″<<d.day<<″/″<<d.year<<endl; //引用Date类对象中的私有数据
cout<<hour<<″:″<<minute<<″:″<<sec<<endl; //引用本类对象中的私有数据
}
Date∷Date(int m,int d,int y) //类Date的构造函数
{
month=m;
day=d;
year=y;
}
int main( )
{
Time t1(10,13,56); //定义Time类对象t1
Date d1(12,25,2004); //定义Date类对象d1
t1.display(d1); //调用t1中的display函数，实参是Date类对象d1
return 0;
}
4， 将下面程序改为在类模板外定义各成员函数：
#include <iostream>
using namespace std;
template<class numtype> //定义类模板
class Compare
{
public:
Compare(numtype a,numtype b)
{
x=a;y=b;
}
numtype max( )
{
return (x>y)?x:y;
}
numtype min( )
{
return (x<y)?x:y;
}
private:
numtype x,y;
};
int main( )
{
Compare<int> cmp1(3,7); //定义对象cmp1，用于两个整数的比较
cout<<cmp1.max( )<<″ is the Maximum of two integer numbers.″<<endl;
cout<<cmp1.min( )<<″ is the Minimum of two integer numbers.″<<endl<<endl;
Compare<float> cmp2(45.78,93.6); //定义对象cmp2，用于两个浮点数的比较
cout<<cmp2.max( )<<″ is the Maximum of two float numbers.″<<endl;
cout<<cmp2.min( )<<″ is the Minimum of two float numbers.″<<endl<<endl;
Compare<char> cmp3(′a′,′A′); //定义对象cmp3，用于两个字符的比较
cout<<cmp3.max( )<<″ is the Maximum of two characters.″<<endl;
cout<<cmp3.min( )<<″ is the Minimum of two characters.″<<endl;
return 0;
}
5， 有两个矩阵a和b，均为2行3列，求两个矩阵的和。重载运算符“+”使之用于矩阵相加。如：c=a+b。重载插入运算符“<<”和流提取运算符“>>”，使之能用于该矩阵的输入和输出。
6， 利用类继承分别完成一个学生类、一个大学生类、一个本科生类，本科生类中包括了一个学生作为他的班长。在创建一个本科生对象时赋予他的全部信息，输出该本科生对象的全部信息。
7， 利用c++继承、多态虚函数、构造函数完成以下程序：设计人、老师、学生、大学生、研究生、大四学生等类、其主要属性自己定义，要求包括以下方法：
1） 构造函数，创建对象的主要信息
2） Display，显示每种类对象的主要信息
此外，要求每个类包含一个生日对象，其类型为Birthday类，学生类应该包含一个班主任对象，其类型为老师类。
三、实验要求
将程序源代码压缩后提交至学院FTP上对应实验和班级的目录中。
作业命名方式为：“学号姓名.rar”。
作业提交时间：下次实验课前提交。
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Author: zhuchao0731@163.com |
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Description: 幂法求矩阵的特征值和特征向量
算法9.1
1． 输入矩阵A，初始向量X，误差限ε最大迭代次数N。
2． 置k=1，u=0。
3． 求xr=>λ，|xr|=max|xr|,i=1,….,n。
4． 计算
Y=X/λ，X=AY
5． 若|λ-u|〈ε，输出λ，X，停机；否则，转步骤6。
6. 若k<N，k+1=>k，λ=>u,转步骤3；否则，输出错误信息，停机
-Power-law matrix eigenvalue and eigenvector algorithm 9.11. Input matrix A, the initial vector X, the error ε maximum iteration limit N. 2. Home k = 1, u = 0. 3. For xr => λ, | xr | = max | xr |, i = 1, ...., N. 4. Calculation Y = X/λ, X = AY5. If | λ-u | <ε, the output λ, X, downtime Otherwise, switch to step 6.6. If k <N,k+1=> k, λ => u, to Step 3 Otherwise, output an error message , parking
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Description: DirectX开发人员使用,3DMax导出X文件插件,解压后考入插件目录-development of the use of DirectX, MAX plug-derived X documents, unpacked admitted plugin directory
Platform: |
Size: 283648 |
Author: hml |
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Description: ％ [BestPop,Trace]=fmaxga(FUN,LB,UB,eranum,popsize,pcross,pmutation)
％ Finds a maximum of a function of several variables.
％ fmaxga solves problems of the form:
％ max F(X) subject to: LB <= X <= UB
％ BestPop--------最优的群体即为最优的染色体群
％ Trace----------最佳染色体所对应的目标函数值
％ FUN------------目标函数
％ LB-------------自变量下限
％ UB-------------自变量上限
％ eranum---------种群的代数,取100--1000(默认1000)
％ popsize--------每一代种群的规模；此可取50--100(默认50)
％ pcross---------交叉的概率,此概率一般取0.5--0.85之间较好(默认0.8)
％ pmutation------变异的概率,该概率一般取0.05-0.2左右较好(默认0.1)
％ options--------1×2矩阵,options(1)=0二进制编码(默认0),option(1)~=0十进制编码,option(2)设定求解精度(默认1e-4)- [BestPop, Trace] = fmaxga (FUN, LB, UB, eranum, popsize, pcross, pmutation) Finds a maximum of a function of several variables. Fmaxga solves problems of the form: max F (X) subject to : LB <= X <= UB BestPop-------- optimal chromosome groups is the best group Trace---------- chromosome corresponding to the best objective function value FUN------------ objective function LB------------- variable lower limit since the UB------------- variable upper limit eranum--------- populations algebra, take 100- 1000 (default 1000) popsize-------- population size of each generation this desirable 50- 100 (default 50) pcross--------- crossover probability, the probability of a general check 0.5- 0.85 between the better (default 0.8) pmutation------ mutation probability, the probability of 0.05 general admission better about-0.2 (default 0.1) options-------- 1 × 2 matrix, options (1) = 0 binary code (default 0), option (1) ~ = 0 decimal coding, option (2 ) set accuracy (default 1e-4)
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Author: mmcc |
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Description: 1.功能
利用广义逆求解无约束条件下的优化问题(C语言)
2.参数说明
int m : 非线性方程组中方程个数
int n : 非线性方程组中未知数个数
double eps1 : 控制最小二乘解的精度要求
double eps2 : 用于奇异值分解中的控制精度要求
double x[n] : 存放非线性方程组解的初始近似值X(0),要求各分量不全为0
int ka : Ka＝max{m,n}+1
void (*f)() : 指向计算非线性方程组中各方程左端函数值的函数名(用户自编)
void (*s)() : 指向计算雅可比矩阵的函数名
int ngin() : 函数返回一个标志值
3.文件说明
ngin.c函数文件
ngin0.c主函数文件-1. Using generalized inverse function for non-binding under the conditions of optimization problems (C) 2. Parameter Description int m : nonlinear equation group number int n equation : nonlinear equations were unknown number of double eps1 : Least Squares Solutions of control precision double eps2 : for the singular value decomposition of the control precision double x [n] : Nonlinear storage solutions of equations initial approximation of X (0), the requirements for the component failure 0 int ka : Ka = max (m, n) a void (* f) () : Calculation of nonlinear equations at the Group of the equation extreme value of the function name (user self) void (* s) () : at the Jacobian matrix calculation of the function name ngin int () : function returns a value of three signs. This document explains
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Author: 罗坤 |
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Description: function y_cum = cum2x (x,y, maxlag, nsamp, overlap, flag)
％CUM2X Cross-covariance
％ y_cum = cum2x (x,y,maxlag, samp_seg, overlap, flag)
％ x,y - data vectors/matrices with identical dimensions
％ if x,y are matrices, rather than vectors, columns are
％ assumed to correspond to independent realizations,
％ overlap is set to 0, and samp_seg to the row dimension.
％ maxlag - maximum lag to be computed [default = 0]
％ samp_seg - samples per segment [default = data_length]
％ overlap - percentage overlap of segments [default = 0]
％ overlap is clipped to the allowed range of [0,99].-function y_cum cum2x = (x, y, maxlag. nsamp, overlap, flag)% CUM2X Cross-covariance% y_cum cum2x = ( x, y, maxlag, samp_seg, overlap, flag)% x, y-data vectors/matrices with identical dimen sions% if x and y are matrices. rather than vectors. % columns are assumed to correspond to independ ent realizations,% overlap is set to 0, and samp_seg dimension to the row. % maxlag-max imum lag to be computed [default = 0]% samp_seg- samples per segment [default = data_length] o% verlap-percentage overlap of segments [defau lt = 0]% overlap is clipped to the allowed range o f [0,99].
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Size: 1024 |
Author: keke |
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Description: 功能说明：
次组件提供的功能有二：
1、解析出数学表达式中的参数
2、计算数学表达式
此组件不但可以解析和计算数学表达式，还提供了一系列的数学基本函数，可应用于表达式中一块处理。提供的数学基本函数有：将值舍入到最接近的整数 rount(x)、向下取整函数 int(x)、向上取整 ceiling(x)、求两个数中最大数的函数 max(a,b)、求两个数中最小数的函数 min(a,b)、幂函数 pow(x,n)、求平方根的函数 sqrt(x)。
下载地址：http://www.qiusuo365.com/qiusuo365/viewthread.php?tid=2422&extra=page％3D1-Functional Description : sub-components provided by the two functions : one, to figure out the mathematical expression of two parameters. calculate mathematical expression of this component will not only analytical and computational mathematical expression, but also provided a series of basic math functions, expression can be applied to a handle. The basic function of mathematics : the value of rounding to the nearest integer rount (x), downward for the entire function int (x), up from the entire ceiling (x), 2 for the largest number of the number of function max (a, b), 2 for the smallest number of the number of function min (a, b), power function pow (x, n), for the square root function sqrt (x). Download Address : http :// www.qiusuo365.com/qiusuo365/viewthread . php tid = 24
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Author: jason |
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Description: 很多出学direct3d的人都在转换x文件时犯难，其实可以用3ds max输出的文件，这是实现方法-Direct3D school, many people are converting to stir up troubles for x files, in fact, can be used 3ds max output file, this is the way to realize
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Size: 4096 |
Author: zyc |
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Description: 用中规模MSI基本逻辑功能模块 实现关模比较器（要求分别使用中规模和语言实现）：
功能要求：它的输入是两个8位无符号二进制整数X和Y，以及一个控制信号S；输出信号为1个8位无符号二进制整数Z。输入输出关系为：当S=1时， Z=min(X,Y)；当S=0时， Z=max(X,Y)。(Modeling comparator is implemented by using basic logic function modules of medium-scale MSI (medium-scale and language are required respectively):
Functional requirements: Its input is two 8-bit unsigned binary integers X and Y, and a control signal S; the output signal is an 8-bit unsigned binary integer Z. The relationship between input and output is: when S = 1, Z = min (X, Y); when S = 0, Z = max (X, Y).)
Platform: |
Size: 10240 |
Author: 瘾1581 |
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